6x-3x^2-12x+2x^2+x^2=16

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Solution for 6x-3x^2-12x+2x^2+x^2=16 equation:



6x-3x^2-12x+2x^2+x^2=16
We move all terms to the left:
6x-3x^2-12x+2x^2+x^2-(16)=0
We add all the numbers together, and all the variables
-6x-16=0
We move all terms containing x to the left, all other terms to the right
-6x=16
x=16/-6
x=-2+2/3

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